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Solve the IVP (yx 2 ) dy dx2x (y2x) = 0, y (1) = 1/3 (3 points) 2 Solve the IVP xy 0 ?What is domain and range?Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Consider the region bounded by {eq}y = 2x^2x1 \enspace and \enspace y = x^21 {/eq} What is the volume of the solid obtained by rotating this region about the yaxis?1x 2 when x 1 »f(p 1 =025) and x 2 »f(p 2 =075) are independent point binomials (MATHSTATS 97) Answer It is straightforward to show that V(x 1)=V(x 2)=pqwhere p= p 1 and q = p 2 are used for ease of notation Since x 1;x 2 are statistically independent, it follows that V(x 1 x 2)=V(x 1)V(x 2)=2pq Alternatively, we may consider theGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
Divide 0 0 by − 8 8 Multiply − 1 1 by 0 0 Add − 1 1 and 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k kDraShukla draShukla Math Secondary School answered The x2 is positive so the general graph shape is ∪ Consider the generalised form of y = ax2 bx c The bx part of the equation shifts the graph left or right You do not have any bx type of value in your equation So the graph is central about the yaxis The c part of the equation is of value 1 so it lifts the vertex up from y=0 to y=1
Solve and graph y < 2x – 1 y ≤ x 2 Consider the line through (1, 1) and (2, 3) Write the equation of the line in pointslope, slopeintercept, and standard form, and find its xintercept Find the zero of P (x) = 7x 12 check_circleMidterm 2 Sample question solutions Math 125BWinter13 1 Suppose that f R3 → R2 is defined by f(x,y,z) = x2 yz,sin(xyz) z (a) Why is f differentiable onA) (0, 2) B) (2, 0) C) (1, 3) D) (0, 2) 7) x = y 3 x 3y = 13 What is the solution to the system of equations?



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516 Solved Problems Consider two random variables X and Y with joint PMF given in Table 53 Find P(X ≤ 2, Y ≤ 4) Find P(Y = 2 X = 1) Are X and Y independent? x 2 y = x 2 What is the solution to the system of equations?To find a solution that passes through the point (2,6), we set x = 2 and y =6 in the general solution and solve for C 6=23 −22 C =8− 4C which implies C =2 Thus, y = x3 − x2 2 is a solution of the differential equation that satisfies the given condition In fact, itis theonly solutionthatsatisfiesthe conditionsince the



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$\begingroup$ Am I also correct to say that the solution is only defined when x^2 15/4 >= 0 x^2 >= 15/4 x >= sqrt(15/4) or x = sqrt(15/4)?Consider the following equation Name the vertical asymptote(s)x = 1 and x = 2y = 1 and y = 2x = 1/4y = 1/4x = 0y = 0 becauseEC02 Spring 06 HW5 Solutions 3 Problem 321 • The random variable X has probability density function fX (x) = ˆ cx 0 ≤ x ≤ 2, 0 otherwise



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The range of y is always based on the y=2x/1 x^2 equation There the range would be (infinity, infinity) as it is for the x domain Just putting y into another calculation should not affect it's range Now if you change the second line to an actual equation, then how y is used would affect its domain in the new equation17 Questions Show answers Question 1 SURVEY 1 seconds Report an issue Q Which inequality is graphed on the given coordinate plane?A) no solution B) one



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To zoom, use the zoom slider To the left zooms in, to the right zooms out When you let go of the slider it goes back to the middle so you can zoom more You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original clickFind the equation of the tangent line stepbystep \square! To solve this question, we can sub in 2x wherever we see a y in our original equation (substitution method) x^2 x(2x) (2x)^2 = 1 x^2 2x^2 4x^2 = 1 3x^2 = 1 x^2 = 1/3 x = sqrt(1/3) STEP 5 Now that we know the xvalue of the point, we can easily find the yvalue of the point because we know y=2x where the tangent line is horizontal



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Sponding point (1;0) is one of the corners, and we will consider it separately below the line y= 0 f(x;0) = x2 2x Computing the derivative and setting it to 0 we find 2x 2 = 0 =)x= 1 This gives the corner (1;0) as before the line y= 2 f(x;2) = x2 2x4 with critical point x= 1 which is again a corner Finally, we check the four cornersAlgebra Calculator is a calculator that gives stepbystep help on algebra problems See More Examples » x3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank youSolutions Section 26 The material beginning on page 98, Integrating Factors for Exact Equations, will not be on the exam 1 Problem 1 (2x3)(2y −2)y0 = 0 We want f



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Y = k − p y = k p Substitute the known values of p p and k k into the formula and simplify y = 7 2 y = 7 2 y = 7 2 y = 7 2 Use the properties of the parabola to analyze and graph the parabola Direction Opens Down Vertex ( − 2, 3) ( 2, 3) Focus ( − 2, 5 2) ( 2, 5 2) Axis of Symmetry x = − 2 x = y – 1 = 2(x – 2) y1 = 2x 4 add 1 on both sides y = 2x 3 To graph the given equation we make a table Plug in some number for x and find out the value of y x y = 2x31 2(1)3= 5 0 2(0) 3= 3 1 2(1) 2= 1 The point to get the graph of the given equation isGraph the quadratic function f(x)=x^22x3Find its Vertex Form ( completing the square)Find the x and y interceptsFind the axis of symmetryFind its domain a



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Consider (2x1) is any variable and differentiate it the same way as you would differentiate y=x^n Which is dy/dx = n*x^ (n1) So di Continue Reading Here chain rule will be applied Consider (2x1) = a Now differentiate on both sides with respect to 'a', we get, 2dx/da = 1 So, dx/da = 1/2Answer to Consider the parabola y = 4x x^2 Graph the parabola and the tangent line to the parabola at the point (1, 3) By signing up, you'llTo find P ( X ≤ 2, Y ≤ 4), we can write P ( X ≤ 2, Y ≤ 4) = P X Y ( 1, 2) P X Y ( 1, 4) P X Y



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Consider y=2x/1x^2, where x is real then the range of the expression y^2y2 is a,b find b4a Get the answers you need, now!1 Consider a random variable X with the following probability mass function x 3 0 1 2 f(x) 2 3 4 c Find P(X > 02) (hint you need to nd c rst) (a) 4 (b) 8 (c) 7 (d) 5 2 An insurance company o ers its policyholder a number of di erent premium payment options ForConsider the random variable X with probability density function f (x) = x/2 for 0 < x < 2 Find P (X < 1) Find E (X) Write the cumulative distribution function of X, F (x) Be sure to define F (x) for infinity < x < infinity Consider the transformation Y = 2X 1 Find the cumulative distribution function of Y and the probability density function of Y



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Simplifying 2x 1y = 1 Solving 2x 1y = 1 Solving for variable 'x' Move all terms containing x to the left, all other terms to the right Add 'y' to each side of the equation 2x 1y y = 1 y Combine like terms 1y y = 0 2x 0 = 1 y 2x = 1 y Divide each side by '2' x = 05 05y Simplifying x = 05 05y1;x 2 2X and y 1;y 2 2Y such that v 1 = x 1 y 1 and v 2 = x 2 y 2 (This is from the de nition of the sum of two subspaces) Now cv 1 v 2 = c(x 1 y 1)(x 2 y 2) = (cx 1 x 2)(cy 1 y 2), and since Xand Y are subspaces, we deduce that cx 1 x 2 2Xand cy 1 y 2 2Y, so their sum cv 1 v 2 is in X Y Thus X Y is a subspace (It is nonempty because both Xand Y are) 3Y = (x y) ln xy x , y (1) = 3 (Hint This is a homogeneous ODE) (3 points) 3 Solve the IVP (ln y 2x?1)y 0 = 2y, y (1) = e (Hint Seek an integrating factor solely dependent on y) ( 3 points) 4



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The expression for the horsepower of an engine is P = 04 n x 2 where n is the number of cylinders and x is the bore of cylinders Determine the power differential added when four cylinder car has the cylinders rebored from 325 cm to 3265 cm THeorem Double Integrals over Nonrectangular Regions Suppose g(x, y) is the extension to the rectangle R of the function f(x, y) defined on the regions D and R as shown in Figure 1421 inside R Then g(x, y) is integrable and we define the double integral of f(x, y) over D by ∬ D f(x, y)dA = ∬ R g(x, y)dA If log y = tan1 x, then show that (1 x2)d2y/dx2 (2x 1)dy/dx = 0 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries



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`(x^2)/(a^2)(y^2)/(b^2)=1` where a is half the length of the major axis and b is half the length of the minor axis For the volume formula, we will need the expression for y 2 and it is easier to solve for this now (before substituting our a and b )A) (1, 4) B) (4, 1) C) (7, 4) D) (25, 55) 8) How many solutions can be found for the system of linear equations represented on the graph? Preview Activity 181 Consider the function y = g(x) = − x2 3x 2 Use the limit definition of the derivative to compute a formula for y = g′(x) Determine the slope of the tangent line to y = g(x) at the value x = 2 Compute g (2) Find an equation for the tangent line to y = g(x) at the point (2, g (2))



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11 Solve y2x1 = 0 Tiger recognizes that we have here an equation of a straight line Such an equation is usually written y=mxb ("y=mxc" in the UK) "y=mxb" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis InThis calculator can be used to expand and simplify any polynomial expressionAdd 1 to both sides Add 1 to both sides 2x=y1 2 x = y 1 Divide both sides by 2 Divide both sides by 2 \frac {2x} {2}=\frac {y1} {2} 2 2 x = 2 y 1 Dividing by 2 undoes the multiplication by 2



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The Questions and Answers of consider y=2x/1x², where x is real , then the range of expression y²y2 is a,b Find b 4a Please solve this quadratic problem are solved by group of students and teacher of Class 11, which is also the largest student community of Class 11EC02 Spring 06 HW3 Solutions 3 Problem 224 • The random variable X has PMF PX (x) = ˆ c/x x = 2,4,8, 0 otherwise (a) What is the value of the constant c?The domain of a function, D D, is most commonly defined as the set of values for which a function is defined For example, a function f (x) f ( x) that is defined for real values x x in R R has domain R R, and is sometimes said to be "a function over the reals" The set of values to which D D is sent by the function is



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